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[perl] 不知道陣列該多大時的小技巧

Posted on 十一月 3rd, 2004 in hacker, phd_student.Visited (0/2545) times

寫文字處理程式總會遇到一些小問題，例如對於不知道字頻範圍，卻又想要記錄下來，許多時候就不知不覺變成寫死的程式碼，指定要記錄那些範圍的頻率。
這是原先的程式碼：

my $count = 0;
my $count2 = 0;
my $count3 = 0;
my $count4 = 0;
my $count5 = 0;
my $count6 = 0;
my $count7 = 0;
my $count8 = 0;
my $count9 = 0;
my $count10 = 0;
my $count11 = 0;
for my $word (keys %word_tag) {
# at least one tag and one COUNT
$count11++ if (keys %{$word_tag{$word}}) == 12;
$count10++ if (keys %{$word_tag{$word}}) == 11;
$count9++ if (keys %{$word_tag{$word}}) == 10;
$count8++ if (keys %{$word_tag{$word}}) == 9;
$count7++ if (keys %{$word_tag{$word}}) == 8;
$count6++ if (keys %{$word_tag{$word}}) == 7;
$count5++ if (keys %{$word_tag{$word}}) == 6;
$count4++ if (keys %{$word_tag{$word}}) == 5;
$count3++ if (keys %{$word_tag{$word}}) == 4;
$count2++ if (keys %{$word_tag{$word}}) == 3;
…
}

然後之後再一個一個輸出，現在改寫成讓它自己生

my @counts;
for my $word (keys %word_tag) {
$counts[(keys %{$word_tag{$word}})-1]++; # at least one tag and one COUNT
…
}
for my $i (1..$#counts) {
print “$i Tag words is “.$counts[$i].”n”;
}

其實可以再簡潔一點，不過我覺得這樣就很夠了 :p

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